Electric bulb 800 contain 36 defective bulbs.one bulb is taken at random out of the box.what is the probability that the bulb chosen is non defective
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5
non defective bulbs = 800-36 = 764 bulbs.
probability = 764/800 = 0.955
probability = 764/800 = 0.955
Answered by
4
total bulbs=800
p(getting defective bulb)=36/800 =0.045
p(getting non defective bulb)=800-36/800
p(getting defective bulb)=36/800 =0.045
p(getting non defective bulb)=800-36/800
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