electric charge q,q and -2q are placed at the corners of an equilateral triangle of side 'a' find electric dipole moment of the system?
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Answer:
Explanation:
Configuration of charges:
Imagine charges at C(−2Q) be splited into charges of (−Q) each so that (AC) and (BC) form two dipole systems.
Now, dipole moment is:
⇒P 1 = QA = p 2,
using vector addition :
⇒P net=√P²1+P²2+2+P1P2cos θ [θ=60°],
⇒P net=QA√3.
Hope it helps.
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