Question

Electric charges - 1000 uC are placed at points A and
B respectively at a distance of 2 m from each other.
Calculate the electric fields at (i) mid-point of the line
to the line
AB and (ii) a point at equal distances of 4 m from each
charge​

Answer 1

Answer:

Here the point at which the electric field has to be found forms an isosceles triangle with both the charges each 4m from the equatorial point .This point lies on the equatorial point.E = k*2aq/(r2 +a2)3Here r = altitude = √15a = 1 m = 1/2 the distance from each charge.K = 9*10^92a = 2mSubstituting the values in the above formula we get,E = 2.8 *10^5N/C.

For being 4m away from each charge ..it must form an isosceles triangle.the charge will be on the equatorial line of the dipole.the formula will be -k4aq/r*r*r