electric current
CODIUMID SULE
6 If resistance of an electric bulb is 500 Q and voltage across its ends is 250 V then power
consumed by it is
a) 130 W
b) 125 W
c) 200 w
d) 120 W
Answers
Answered by
2
Answer:
b. 125W
Explanation:
R=500ohm
V=250V
As P=V^2/R
=250×250/500
=125W
Answered by
1
Answer:
Option(b) 125w
Explanation:
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Power = v²/r
Therefore
P = 250²/500
P = 125w
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