Physics, asked by bishtkavita3156, 3 months ago

electric current of 200uA flow in a wire for 30 second.calculate a.amount of charge passed through wire.b. number of electrons passed through the wire.​

Answers

Answered by vipinkumar212003
2

Explanation:

electric \: current \:(I)  = 200μA= 200 \times  {10}^{ - 6}A  \\ time(t)= 30 s \\ (a): \: Q=?  \\ I= \frac{Q}{t}  \\ Q=I \times t \\  = 200 \times  {10}^{ - 6}  \times 30 \\  = 6 \times  {10}^{ - 3} c \\ (b): \: number  \:  of \: electron \times charge\:on\: electron\\=charge \: given \\ n {e}^{ - }  = Q \\ n =  \frac{Q}{ {e}^{ - } }  \\  =  \frac{6 \times  {10}^{ - 3}}{1.6 \times  {10}^{ - 19} }  \\  =  \frac{6}{1.6}  \times  {10}^{ - 3 + 19}  \\  = 3.75 \times  {10}^{16}  \: electrons

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