Question

electric field and electric potential inside a charged spherical shell is​

Answer 1

Since there is no field inside the shell, the potential at any point inside the shell is equal to the potential on the surface of the shell, V=Q4πϵ0. ... Inside the sphere, the field is zero, therefore, no work needs to be done to move the charge inside the sphere and, therefore, the potential there does not change.

Answer 2

Answer:

Electric field = $0$.

Electric potential = constant.

Explanation:

Electric field:

Consider the point P placed inside the shell. The Gaussian surface has a radius r. The Gaussian surface contains no charge inside it.

Hence, $q=0$

Therefore,

$E = 0$

Hence, we can say that the electric field inside the spherical shell is always zero.

Electric potential:

$W=qV$ is the amount of work required to transfer a charge $q$ from point A to point B.

The difference in potential between any two sites in the interior of the spherical shell is zero since the potential in the interior does not change (because the field is zero, $E=-\frac{dV}{dx}$).

In other words, no work is done in transporting a charge inside the spherical shell.