Question

Electric field and electric potential inside a charged spherical shell- * 1 point E = 0; V= 0 E = 0; V ≠0 E ≠ 0; V= 0 E ≠ 0; V ≠0

Answer 1

Answer : E=0 AND V≠0

Answer 2

The electric field and electric potential inside a charged spherical shell are zero and a constant respectively.

That is, E = 0, V ≠ 0

Consider a uniformly charged spherical shell

If we consider point p inside the shell, Then this gaussian surface has no charge at all.

We know, E = $\frac{q}{4\pi r2}$

where 'E' is the electric field, 'r' is the distance from the center, 'q' and is the charge.

As q = 0, E = 0

We know the electric field inside the uniformly charged sphere is zero.

E = $\frac{-dV}{dr}$ = 0, where 'E' is the electric field, 'V' is the voltage, and E is the distance from the center.

That is $\frac{dV}{dr}$ = 0

or in other words, V is a constant