electric field at a point 0.9 M away from a point charge 1.8 μc is
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Answer:
Explanation:
according to Gauss theorem,
electric flux is the ratio of charge inclosed into the Gaussian surface and permittivity of medium. e.g.,
here, q is charge inclosed into the Gaussian surface.
given, q = 2 × 10^-6 C and
=8.85 × 10^-12 C²/Nm²
now, electric flux = 2 × 10^-6/8.85 × 10^-12
= 0.23 × 10^6 Nm²/C
hence, electric flux through the surface is 2.3 × 10^5 Nm²/C
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