Question

electric field components are Ex = 100 x^1/2 Ey= Ez=0 . Calculate net flux through the cube placed in electric field at shown position.​

Answer 1

Answer:

Solution

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Correct option is

A

9.3×10

−12

C

Flux at surface x=aϕ

a

=a

2

×(αa

2

1

)

(as area element is outside and E is directed inside)

∴ϕ

a

=−αa

2.5

Flux at the surface ϕ

2a

=a

2

×(α(2a)

2

1

)

ϕ

2a

=α

2

⋅a

2.5

total flux =αa

2.5

(

2

−1)

we know ϕ=

ε

0

q

⇒q=αa

2.5

(

2

−1)×8⋅85×10

−12

C

∴q=800×(0⋅1)

2

×

0⋅1

(0⋅414)×8⋅85×10

−12

C

q=29.427×

0⋅1

×10

−12

∴q=9.303×10

−12

C.