Question

electric field in a region is radially outward and at a point is given by E is equal to 250rV/m calculate the charge contained in a sphere of radius 20cm centered at origin

Answer 1

Answer:

The charge will be $q=2.22\times10^{-10}\ C$.

Explanation:

Given that,

Electric field E = 250r V/m

Radius = 20 cm = 0.2 m

We know that,

The electric field is defined as:

$E = \dfrac{kq}{r^2}$

Where, E = electric field

k = constant

q = charge

r = distance

We substitute the value into the formula

$250\times 0.2=\dfrac{9\times10^{9}\times q}{0.2\times 0.2}$

$q = \dfrac{250\times0.2\times (0.2)^2}{9\times10^{9}}$

$q=2.22\times10^{-10}\ C$

Hence, The charge will be $q=2.22\times10^{-10}\ C$.

Answer 2

the answer is 2.22 × 10*-8