Question

Electric field in the figure is directed along x-axis i.e. Ex = 5 AX+2B.
Where, E is in N/C. Xin metre & A.B are constants, A=10NC m and
B=5N NC m)
Calculate-
(a) is E. flux passing through all the surfaces of the cube?
(b) determine E. flux passing through M & N surfaces respectively.
e) determine E. flux passing through the cube.
1) determine the net charge enclosed within the cube.​

Answer 1

Answer:

Electric field in the given figure is directed along +X direction and given by Ex=5Ax+2B, where E is in NC−1 and x is in metre, A and B are constants with dimensions. Taking A=10 NC−1m−1 and B=5 NC−1, calculate

(i) The electric flux through the cube.

(ii) Net charge enclosed within the cube.

Explanation:

Given Ex=5Ax+2B

The electric field at face M where x=0 is

E1=2B

The electric field at face N where x=10 cm=0.10 m is

E2=5A×0.10+2B=0.5 A+2B

The electric flux through face M is

φ1=E1⋅S1=E1S1cosπ=−E1S1

=−2B×l2 where l=10 cm=0.01 m

The electric flux through face N

φ2=E2⋅S2=E2S2cos0=(0.5A+2B)l2

Net electric flux, φ=φ1+φ

Answer 2

Explanation:

I hope it Will help you..