Question

Electric field intenisty at any point due to an ideal dipole (Derivation)
(3 mark)​
this is the question of physics, by mistake, that science was selected by me......sorry

Answer 1

I can't understand this question...........☹

Answer 2

Suppose, we take z axis along dipole . The point z=0 is at the center of the dipole. The distances of different points are measured from z=0. We take dipole made of -q and +q situated at z=-a and z=+a. Then dipole moment is vector pp^, where p^ is unit vector in the direction from -q to +q. The magnitude of dipole moment is p= 2aq. The electric field intensity E(z), at z=z point on the axis of dipole is given by

E(z)= 2kpzp^/(z^2- a^2)^2.

Here, k is constant appearing in Coulomb's law.

Note that E is vector in the direction of p^.

If z>>a, then dipole can be regarded as small and a^2 can be neglected as compared to z^2. Then we have

E(z)=(2kp/z^3)p^