Physics, asked by rraj2295, 11 months ago

electric field intensity and electric field potential ​

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Answered by avats673
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Explanation:

An electric potential (also called the electric field potential, potential drop or the electrostatic potential) is the amount of work needed to move a unit of charge from a reference point to a specific point inside the field without producing an acceleration. Typically, the reference point is the Earth or a point at infinity, although any point can be used

In classical electrostatics, the electrostatic field is a vector quantity which is expressed as the gradient of the electrostatic potential, which is a scalar quantity denoted by V or occasionally φ,[1] equal to the electric potential energy of any charged particle at any location (measured in joules) divided by the charge of that particle (measured in coulombs). By dividing out the charge on the particle a quotient is obtained that is a property of the electric field itself. In short, electric potential is the electric potential energy per unit charge.

This value can be calculated in either a static (time-invariant) or a dynamic (varying with time) electric field at a specific time in units of joules per coulomb (J C−1), or volts (V). The electric potential at infinity is assumed to be zero.

In electrodynamics, when time-varying fields are present, the electric field cannot be expressed only in terms of a scalar potential. Instead, the electric field can be expressed in terms of both the scalar electric potential and the magnetic vector potential.[2] The electric potential and the magnetic vector potential together form a four vector, so that the two kinds of potential are mixed under Lorentz transformations.

Practically, electric potential is always a continuous function in space; Otherwise, the spacial derivative of it will yield a field with infinite magnitude, which is practically impossible. Even an idealized Point Charge has {\displaystyle 1/r}1/r potential, which is continuous everywhere except the origin; The Electric field across an idealized Surface charge is not continuous, but it's not infinite at any point. Therefore, the electric potential is continuous across an idealized Surface charge. An idealized Linear Charge has {\displaystyle \ln(r)}{\displaystyle \ln(r)} potential, which is continuous everywhere except on the Linear Charge.

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