electric field intensity at point 'B' due to a point charge 'Q' kept at a point 'A' is 24N/C and the electric potential at a point 'B' due to same charge is 12J/C.calculate the distance Ab and also the magnitude of charge Q.
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E=kq/r^2
P= kq/r
E/P=1/r
24/12=1/r
2= 1/r
R=.5m=ab
Q= Pxr/k
= 12x.5/9x10^9
=. 67x 10^-9c
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