Physics, asked by joshuarajujr8185, 1 year ago

Electric field intensity at various points due to a uniformly charged spherical shell (thin & thick both).


subhanssk: Electric Field Intensity at various points due to a uniformly charged spherical shell (thin & thick both).
subhanssk: What is the exact answer

Answers

Answered by arjun7774
0

It is easy to show that an area of surface density causes only one electric field (outside the sphere) in the form of a point charge at the center (use Gauss law and symmetry).

Similarly Gauss law predicts that continuous surface density area does not cause any area within it.

So if you calculate E (r), then you can imagine all the charges inside the ball, which are located in the center.

Answered by subhanssk
0

Electric Field Intensity at various points due to a uniformly charged spherical shell (thin & thick both).

Similar questions