Question

Electric field intensity between two infinite plane parallel sheets of charge of surface charge densities σ and -σ is * (a) σ/2ε₀ (b) σ/ε₀ (c) 2σ/ε₀ (a) σ x ε₀​

Answer 1

Given:

Two infinite plane parallel sheets of charge of surface charge densities σ and -σ.

To find:

Electric Field Intensity ?

Calculation:

First of all, we know that conducting sheets of charge have a field intensity of $\dfrac{\sigma}{2\epsilon_{0}}$

Now, see the attached diagram !

Let net field intensity be E_{net}.

• Field intensity between the plates will be addition of the individual plate field intensity.

$\rm \: E_{net} = \dfrac{ \sigma}{ 2 \epsilon_{0 } } + \dfrac{ \sigma}{ 2 \epsilon_{0 } }$

$\rm \implies\: E_{net} = \dfrac{ 2\sigma}{ 2 \epsilon_{0 } }$

$\rm \implies\: E_{net} = \dfrac{ \sigma}{\epsilon_{0 } }$

So, option b) is correct !