Physics, asked by kundanmehtassm, 2 months ago

electric field intensity due to a group of charge​

Answers

Answered by sahildudhal
1

Answer:

The electric field intensity at any point due to a system or group of charges is equal to the vector sum of electric field intensities due to individual charges at the same point. Here, ri is the distance of the point P from the ith charge Qi and ri is a unit vector directed from ^Qi to the point P.

Explanation:

Electric field intensity is the strength of an electric field at any point. It is equal to the electric force per unit charge experienced by a test charge placed at that point, or E=qF. From Gauss law, considering a spherical surface with charge at its center as Gaussian surface, E(A)=ϵ0q.

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