Question

Electric field intensity inside uniformly charged solid sphere is directly proportional to the distance from centre of sphere ?

Answer 1

Explanation:

In uniform charge distribution in solid sphere:

E= K ×Q r/R^3.

Thank you.

Answer 2

• Inside,

               $r < R$,

therefore we can write as,

The gaussian surface of radius r,

Ф = Ф$E.dACos0^{0}$

   $=E$Ф $dA$

  $=E(4\pi r^{2})$

• lets find for inside,

                $q_{in} =E(4\pi r^{2} )($ε$)$

                     $=$${4}{3} \pi r^{3$$/$ε

                  $E=$ρ$r$$/3$ε

therefore

$E\alpha r$

• Let's take the total; charge as Q,

                       $d=\frac{Q}{\frac{4}{3} \pi r^{3} }$  

                (d= ρ= density)

• lets substitute this value in the above equation,

                       $E=\frac{QR}{\frac{4}{3}\pi r^{3} }$  ×$3$ε

• after cancellation the equation would be,

            $E=1/4\pi$ε$(\frac{Qr}{R^{3} })$

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