Question

Electric field intensity of a point at a distance 60 cm from cgarge 2 volt/metre then charge will be

Answer 1

Answer:

can search it on google

Explanation:

Answer 2

The charge will be $8\times 10^{-11}\ C$.

Explanation:

It is given that,

Electric field intensity at a point, E = 2 V/m

Distance from the point, d = 60 cm = 0.6 m

The electric field intensity at a point is given by :

$E=\dfrac{kq}{d^2}$

$q=\dfrac{Ed^2}{k}$

$q=\dfrac{2\times (0.6)^2}{9\times 10^9}$

$q=8\times 10^{-11}\ C$

So, the charge will be $8\times 10^{-11}\ C$. Hence, this is the required solution.

Learn more,

Electric field

https://brainly.in/question/9647443