Question

Electric field is zero in case of a charged conducting shell at any​

Answer 1

Answer The electric field immediately above the surface of a conductor is directed normal to that surface. ... Now, the gaussian surface encloses no charge, since all of the charge lies on the shell, so it follows from Gauss' law, and symmetry, that the electric field inside the shell is zero.

Answer 2

✍️A᭄NSWER✍️

ᴛʜᴇ ᴇʟᴇᴄᴛʀɪᴄ ғɪᴇʟᴅ ɪᴍᴍᴇᴅɪᴀᴛᴇʟʏ ᴀʙᴏᴠᴇ ᴛʜᴇ sᴜʀғᴀᴄᴇ ᴏғ ᴀ ᴄᴏɴᴅᴜᴄᴛᴏʀ ɪs ᴅɪʀᴇᴄᴛᴇᴅ ɴᴏʀᴍᴀʟ ᴛᴏ ᴛʜᴀᴛ sᴜʀғᴀᴄᴇ.

ɴᴏᴡ, ᴛʜᴇ ɢᴀᴜssɪᴀɴ sᴜʀғᴀᴄᴇ ᴇɴᴄʟᴏsᴇs ɴᴏ ᴄʜᴀʀɢᴇ, sɪɴᴄᴇ ᴀʟʟ ᴏғ ᴛʜᴇ ᴄʜᴀʀɢᴇ ʟɪᴇs ᴏɴ ᴛʜᴇ sʜᴇʟʟ, sᴏ ɪᴛ ғᴏʟʟᴏᴡs ғʀᴏᴍ ɢᴀᴜss' ʟᴀᴡ, ᴀɴᴅ sʏᴍᴍᴇᴛʀʏ, ᴛʜᴀᴛ ᴛʜᴇ ᴇʟᴇᴄᴛʀɪᴄ ғɪᴇʟᴅ ɪɴsɪᴅᴇ ᴛʜᴇ sʜᴇʟʟ ɪs ᴢᴇʀᴏ.

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