Physics, asked by ksneha2707, 7 months ago

electric field near a charged plane conductor is.​


ksneha2707: options are a)sigma\absalomnot. (b)simga\2absalomnot (c) absalomnot•sigma. (d)2sigma\absalomnot
Anonymous: B OPTION IS CORRECT
ksneha2707: thnqq
Anonymous: no problem
Anonymous: ur welcome

Answers

Answered by Anonymous
2

Explanation:

The electric field is zero inside a conductor. Just outside a conductor, the electric field lines are perpendicular to its surface, ending or beginning on charges on the surface. Any excess charge resides entirely on the surface or surfaces of a conductor.

Answered by Anonymous
3

HEYA!!UR ANSWER IS THIS ⤵️

The electric field is zero inside a conductor. Just outside a conductor, the electric field lines are perpendicular to its surface, ending or beginning on charges on the surface. Any excess charge resides entirely on the surface or surfaces of a conductor.

SOME FACTS ABOUT IT FOR CLEAR UNDERSTANDING:-)

The properties of a conductor are consistent with the situations already discussed and can be used to analyze any conductor in electrostatic equilibrium. This can lead to some interesting new insights, such as described below.

How can a very uniform electric field be created? Consider a system of two metal plates with opposite charges on them, as shown in Figure 4. The properties of conductors in electrostatic equilibrium indicate that the electric field between the plates will be uniform in strength and direction. Except near the edges, the excess charges distribute themselves uniformly, producing field lines that are uniformly spaced (hence uniform in strength) and perpendicular to the surfaces (hence uniform in direction, since the plates are flat). The edge effects are less important when the plates are close together.

HOPE ITS HELPFUL

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