Physics, asked by niranjanakapardini, 27 days ago

Electric field of an infinitely long charged conductor having linear charge density 10 Cm'at a distance 10 cm from it is 5 00S ta) (6) 50 1 (c) (d) TEO 2πε,​

Answers

Answered by harshavardhan0216
0

Answer:

The Gauss law states that electric flux passing through any closed surface is equal to the charge enclosed by that surface divided by permittivity of vacuum.

By symmetry, the magnitude of the electric field will be the same at all points on the curved surface of the cylinder and directed radially outward. E and ds are along the same direction.

Now here we have the two surfaces, one curved and other the plane caps,

First, the flux through the curved surface,

∮E⋅ds=ϵ0qin

E(2πrl)=λl/ϵ0

E=2πrϵ0λ

Now due to the plane caps,

The angle between E and ds is 90,

so the flux through that part is zero

so, Total flux through the closed surface is,

E=2πrϵ0λ

Explanation:

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Answered by GlimmeryEyes
3

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Pls type ur full question with all options.

The question is not fully completed and options r not there

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