Question

electric field on y axis will be maximum at y= ?​

Answer 1

Step-by-step explanation:

ANSWER

dY

dE

=0

or, when at P is loaded at the perpendicular bisector of a dipole

E=

(n

2

+l

2

)

3/2

P

r=Y

dY

dE

=

dy(Y

2

+l

2

)

3/2

P

=0

=P

dy

d

(Y

2

+l

2

)

−3/2

=0

or, P×

2

−3

(y

2

+d

2

)

−3/2−1

=0

or, P×(−

2

3

)(y

2

+d

2

)

−

2

5

=0

where l=d

Now,

P(−

2

3

)(y

2

+d

2

)

2

−5

=0

or, d

2

+y

2

=0

or, d=−y

or, y=−

2

d

hope its help uhh