Physics, asked by srisayan3787, 1 year ago

Electric flux through a closed surface enclosing an electric dipole is

Answers

Answered by manglamarya786
24

It will be zero...because dipole is combination of positive and negative

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Answered by parulsehgal06
0

Answer:

Electric flux through a closed surface enclosing an electric dipole is zero.

Explanation:

Electric flux:

  • Electric flux is the number of field lines passing through a given surface.
  • We can find electric field orientation by Gauss Law.

Gauss Law:

  • Gauss law states that "The net flux through any hypothetical surface is equal to 1/∈₀ times the net charge within that closed surface".
  • Electric Dipole is a positive and negative charge of equal magnitude at a specific distance.
  • Hence, the total charge inside the cube is zero.
  • The electric field lines begin at the positive charge and stop at the negative charge in an electric dipole.
  • Therefore, if we examine the electric field lines coming from the positive charge, we will find that they contribute to a positive flux at the cube's surface.
  • To reach the negative pole, the identical field lines must cross the side once more. As a result, it will add the equal amount of negative electrical flux.
  • As a result, positive and electric flux cancel one another out to produce zero net electric flux.
  • The electric field lines begin at the positive charge and stop at the negative charge in an electric dipole. Consequently, the electric field lines coming from the positive charge will produce a positive contribution if we examine them.
  • We can take any of the six sides of the box to explain this as shown in figure.

Know more about Electric dipole:

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