Question

electric force between two stationary charges become 1/10th when space between them is filled by a dielectric medium.relative permitivity of the medium is

Answer 1

Answer:

Relative permittivity of medium : 10

Explanation:

Suppose,

permittivity of air = e

permittivity of medium = é

Relative permittivity (K) = é/ę

Force act in air = Fo= q^2/4pi ę r^2

Force act in medium = Fm = q^2/4pi é r^2

Take ratio of Fo/Fm = é/ę = K

so, Fo/Fm K

Given:

Fm = Fo / 10

• Calculation :

K = Fo / Fm = 10

. Answer:

Relative permittivity of medium

: 10