Electric heater draws a current of 5A and its element has resistance of 50 ohm. if the heater is switched on for 5 minutes.calculate the energy released by the heater in KJ.
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power developed=i^2.r=5*5*50=1250 watt
power developed in 5 minutes=5*60*1250=375000 watt
energy consumption=375000joule/sec
power developed in 5 minutes=5*60*1250=375000 watt
energy consumption=375000joule/sec
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