Electric kettle rated at 220 V, 2.2 kW, works for 3 hours. Find he energy consumed and the
current drawn.
Answers
Answered by
241
Power, P = 2.2 kW = 2200 W
Voltage, V = 220 V
Time, t = 3 h = 3 × 3600 = 10800 s
So, the energy consumed is = 2200 × 10800 = 23760000 J
The current drawn is, I = P/V = 2200/220 = 10 A
Voltage, V = 220 V
Time, t = 3 h = 3 × 3600 = 10800 s
So, the energy consumed is = 2200 × 10800 = 23760000 J
The current drawn is, I = P/V = 2200/220 = 10 A
Answered by
45
Answer:
Energy = 23760000 J
Current= 10 A
Explanation:
Power is defined as rate of doing work
Energy is defined as the capacity to do a work.
Now in the given question ,
Power given=2.2 kW = 2200 W
Voltage= 220 V
Time = 3 hours=3 × 3600 = 10800 s
We know the formula for energy is E=Pt where E is the energy P is the power and t is the time taken , so therefore
The energy consumed is = 2200 × 10800 = 23760000 J
The current drawn is, I = P/V = 2200/220 = 10 A
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