electric oven of a 2 kW power rating is operated in a domestie circuit (220 V) that has a current
rating of 5 A. What result do you expect ? Explain.
Answers
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Here...
Power of oven at which it is operating(P)=2kW=2000W
Domestic current potential difference(V)= 220V
Current passing through oven=
P/V
=2000/220
=9.09 A
But the oven has current rating of 5A only. Which means that it would fuse or appliance's circuit will break if the current of more than its current rating(>5 A) will pass through it.
Hence the the fuse/circuit of oven will open
or
short circuit will occur in oven.
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...Hope it helps....
Answer:
★ EFFICIENCY OF ELECTRIC OVEN DECREASES AT LOW POWER SUPPLIED CONDITIONS ★
Explanation:
★ CURRENT ELECTRICITY ★
★ Given ;
» Power of Electric Oven ( P )
[ operating power ] = 2 KW
» Voltage of domestic Circuit( V ) = 220V
» Current ( i ) = 5 Ampere
★ POWER SUPPLIED ( P" ) = ???
_____ [ BY USING FORMULA ] _____
[]
★ P" = 220 × 5
★ P" = 1100 Watt [ OR ] 1.1 KW
_________________________________________
ANSWER :- POWER SUPPLIED TO ELECTRIC OVEN IS ;
[ P" = 1.1 KW ]
—————— [ RESULTS ] ——————
→ we know that ; ←
» POWER SUPPLIED is less than that of Power Required .
» So ; The EFFICIENCY OF Electric Oven to Work " DECREASES " .
» As ; Power Required to work is 2 KW , The heating effect of Oven decreases .
» And also ; It takes more time to Heat an object .
★ IT MAY HAPPEN SOMETIMES DEVICE MAY BECOME AFFECTED AND MAY GETS DAMAGED DUE TO LOW POWER RATING ★