Electric potential at a point 20cm away from a point charge of 4C is
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Answer:
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Explanation:
Given : r=9 cm =0.09 m
Charge Q=3 nC =3×10
−9
C
Potential at a distance 9 cm, V=
r
kQ
where k=9×10
9
∴ V=
0.09
9×10
9
×3×10
−9
=300 V
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