Question

Electric potential energy required to move 2C charge from 9×10^9m towards another charge 3C is ............J​

Answer 1

nhavznaojagsjeosnwkn

Answer 2

Given:

Two charge 2C and 3C is given which are separated by a distance of

9×10^9 m.

To Find:

Electric potential energy required to move 2C charge from 9×10^9m towards another charge 3C ?

Solution:

given;

$q_{0}=2C \ , q_{1}=3C \ and \ d = 9\times10^9 m$

take , k = 9×10^9 N = Coulomb constant.

Since, we know that -

Electric potential energy between these two charges is given by

$U=-\left ( \dfrac{k\times q_{0}q_{1}}{d^2} \right )$

therefore,

$U=-\left( \dfrac{9\times10^9\times2\times3}{(9\times10^9)^2}\right)\\\\= -0.667\times10^{-9}\\=-667 \ p J$

Hence, -667p J electric potential energy is required to move 2C charge from 9×10^9 m towards another charge 3C.