Electric potential in an electric field is given by v=K/r ( K=const). If the posiion vector r = 2i + 3j + 6k, the electric field is given by
A) ( 2i + 3j + 6k) / 243
B) (2i + 3j + 6k) / 343
C) (3i + 2j + 6k) / 243
D) (6i + 2j + 6k) 343
Plz do all the proper.
Answers
Answered by
6
The electric potential due to a system of point charges is equal to the sum of the point charges' individual potentials. This fact simplifies calculations significantly, since addition of potential (scalar) fields is much easier than addition of the electric (vector) fields.
Answered by
5
Answer:
Explanation:
If electric fied is 3i+2j-6k so magnitude will 7 and from integration will 10 and it wipl 10/7×3i+2j-6k
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