Electric potential of a small charged droplet is 5V.
If 27 such droplets are combined to form a single
drop, potential of that drop will be:
(1) 20 V
(2) 450 (3) 15V (4) 135V
Answers
Answer:the answer is 45v. Through the equation, v of bigger droplet= (n)'2/3×v of smaller droplets•
Explanation:5(27)'2/3......
5(3)'2......
---5×9=45v
That I think.
Given : Electric potential of a small charged droplet is 5V. If 27 such droplets are combined to form a single drop
To find : potential of that drop
Solution:
V = kq/r
5 = k q/r
=> q = 5r/k
27 Such droplets are combined
Hence total charge Q = 27q
Q = 27 (5r/k)
Volume of one droplet = (4/3)πr³
Voume of 27 droplets = 27 * (4/3)πr³
= (4/3)π(3r)³
=> R = Radius of bigger Droplet = 3r
V = k Q /R
=> V = k (27 (5r/k) / 3r
=> V = 45
potential of that drop will be 45 V
option 2 - 45 V is correct
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