Question

Electric Potential on the surface of a charged spherical shell of radius 10cm is 50 volt. Find the value of electric potential at a distance of 20cm from the centre of spherical shell.

Answer 1

Answer:

Potential at surface = 50 V 

Potential at surface = 50 V V = \dfrac{K.Q}{R}V=RK.Q

Potential at surface = 50 V V = \dfrac{K.Q}{R}V=RK.Q50 = \dfrac{K.Q}{0.1}50=0.1K.Q

Potential at surface = 50 V V = \dfrac{K.Q}{R}V=RK.Q50 = \dfrac{K.Q}{0.1}50=0.1K.QKQ= 5 

Potential at surface = 50 V V = \dfrac{K.Q}{R}V=RK.Q50 = \dfrac{K.Q}{0.1}50=0.1K.QKQ= 5 potential at 200 m from centre 

V=\dfrac{K.Q}{r}V=rK.Q

V=\dfrac{K.Q}{r}V=rK.QV= \dfrac{5}{0.2}V=0.25 = 25 volt 

Explanation:

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