Question

electric supply of a house is through 15A fuse.when a 2000w heater is used in this house,how many 200 W bulbs can be used simultaneously

Answer 1

Here,
Maximum Current I = 15 A
supply voltage, V = 220 V
so, the maximum power the household circuitary can use is = VI = 220*15 = 3300 W
Heater use 2000 W power
so, remaining power is 3300-2000 = 1300 W
One bulb can used 200 W
so, 1300 W used by no. of bulbs = 1300/200 = 6.5 bulbs

Answer 2

Dear Student,

◆ Answer -

n = 6.5 bulbs

● Explanation -

As this is domestic electric supply, voltage will be 220 V.

Maximum power available is calculated as -

P(max) = VI

P(max) = 220 × 15

P(max) = 3300 W

Let n be no of bulbs used in circuit.

P(heater) + P(bulbs) = Pmax

2000 + n×200 = 3300

n×200 = 3300 - 2000

n×200 = 1300

200n = 1300

n = 1300/200

n = 6.5 bulbs

Hence, 6.5 bulbs are used simultaneously.

Thanks dear. Hope this helps you...