Electrical circuit resistance of 2 ohm and 4 ohm respectively are connected in series to 6 volt watery the heat dissipated by the 4 ohm resistor in 5 second will be
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Explanation:
Net resistence = 2ohm + 4ohm=6ohm
V =6 V
Therefore: current = V/R = 6V/6ohm= 1 A
Heat dissipated
H = l*l*R*t = 1*4*5 = 20J
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