electrical energy and joules law ... explain it and give some key point for long question
Answers
Explanation:
Joule’s Law states that H (Heat) = I (Current) x V (Voltage) x T (Time the current is allowed to flow).
Or, written differently,
H (Heat) = I2 (Current squared) x R (Resistance) x T (Time the current is allowed to flow).
Note: V (Voltage) = I (Current) x R (Resistance), so the two equations are the same, just stated differently. The second version of this law is probably more common in the field.
Joule’s Law is an equation that gives the amount of heat (energy) delivered to something. It would seem sensible to assume that it’s the amount of heat delivered to the weld. However, it is important to consider all the factors in the equation: Current, Voltage, and Time. Joule’s Law assumes that each of these factors remains constant in the secondary of the welding transformer. A weld controller or weld timer may indeed provide a constant amount of current at the electrodes, but recall Ohm’s Law: Voltage equals Current times Resistance, or written differently, Current equals Voltage divided by Resistance.
Factors like pitting or mushrooming of the electrodes, dirty workpieces, changes in force, etc. all have an effect on the surface area (the area of contact) between the electrode and the workpiece. Since changes in the surface area affect the contact resistance (resistance of the surface area), it is reasonable to say that the resistance at the workpiece is not constant, but rather a factor that can change depending on a number of other conditions.
If Resistance is not constant, then according to Ohm’s Law, Current is not constant either. This means that the I-squared version Joule’s Law will not reveal the amount of heat generated at the workpiece unless the resistance at the tips is known.
Simply put, to determine how much heat is being generated at the workpiece using Joule’s Law, current, voltage or resistance must be measured at the workpiece. Although a weld controller may be programmed to deliver 20 KA at 10 Volts, if there is significant resistance in the secondary weld loop, the heat will go there and not to the workpiece. Likewise, if the electrodes are worn or the workpiece is dirty, resistance and current density will be affected. In such a situation, a controller might indicate 10 Volts at the secondary, however there might actually be only 5 Volts at the weld tips.
Such a disparity could easily cause bad welds.
Answer:
H=i^2RT, Heat= product of resistance,square of current and temperature