Question

ELECTRICITY-- Class 10
BOARD EXAM purpose
Question---
Two resistors 3ohms and unknown resistor are connected in series across a 12 volts battery. If the voltage drop across the unknown resistor a 6 volts.

(I) potential difference across 3 ohm resistance.
(ii) current through unknown resistor.
(iii) equivalent resistance of the circuit.

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Answer 1

Answer:

answered below

Explanation:

(i) potential difference across 3 ohm resistance = 12 - 6 = 6 volts

(ii) current through unknown resistor = 6/3 = 2 A.

(iii) equivalent resistance of the circuit = 12/2 = 6 ohms

Answer 2

ANSWER.....

WE DENOTE KNOWN RESISTOR AS (A) AND UNKNOWN RESISTOR AS (B)...

THERE IS YOUR FIRST PART.....

$potential \: difference \: across \: {b} \: is \: 6 \\ \\ total \: potential = potential \: drop \: on \: a \: + potential \: drop \: on \: b \\ \\ total \: potential \: = 12 \: volt \\ \\ potential \: across \: a \: (3ohm) = (12 - 3)volt \\ \\ potential \: difference \: across \: 3ohm = 6 \: volt$

AS WE KNOW THAT THE AMOUNT OF CHARGE IN SERIES COMBINATION IS SAME THROUGHOUT THE COMBINATION.....

THERE IS YOUR SECOND ANSWER...

$potential \: difference \: across \: 3ohm = 6 \: volt \\ \\ resistance = 3 \: ohm \\ \\ v = current \times resistance \\ \\ 6 = current \times 3 \\ \\ current = 2 \:amp$

HERE IS THE VALUE OF UNKNOWN RESISTOR.....

$potential \: difference \: across \: unknown \: resistor = 6volt \\ \\ v = current \times resistance \\ \\ 6 = current \times b \\ \\ current \: remain \: same \: in \: series \: \\ combination \\ \\ 6 = 2 \times b \\ \\ unknown \: resistor = 3ohm$

YOUR LAST PART.....

$in \: series \: combination \: the \: value \\ of \: equivalent \: resistance \: is \: equal \\ to \: the \: sum \: of \: individual \: resistance.. \\ \\ eq \: resistance = a + b = 6ohm$