Question

electricity is passed through copper sulphate which energy comes out

zinc and copper rods are immersed and H²SO and connect to the bulb which energy comes out ​

Answer 1

Answer:

negative

Explanation:

Whenever copper sulfate or CuSO4 is added to water, it gets dissolved in the water. As the CuSO4 is an electrolyte, it splits into Cu

++

(cation) and SO

4

−−

(anion) ions and move freely in the solution. Now if two copper electrodes are immersed in that solution, the Cu

++

ions (cation) will be attracted towards cathode i.e. the electrode connected to the negative terminal of the battery . On reaching on the cathode, each Cu

++

ion will take electrons from it and becomes neutral copper atoms. Similarly the SO

4

−−

(anion) ions will be attracted by anode i.e. the electrode connected to the positive terminal of the battery . So SO

4

−−

ions will move towards anode where they give up two electrons and become SO

4

radical but since SO

4

radical can not exist in the electrical neutral state, it will attack copper anode and will form copper sulfate.

Hence, When electric current is passed through the copper sulfate solution, free copper ions gets drawn to the electrode connected to the negative terminal of the battery and gets deposited on it.