Question

electricity numerical. ................​

Answer 1

Answer:

The electric lamp is connected in parallel with the conductor, The net resistance is given by:

$r = \frac{r1 \times r2}{r1 + r2} \\ r1 = 24 \\ r2 = 6 \\ then \\ r = \frac{24 \times 6}{24 + 6} = 4.8ohm$

$total \: current \: using \: ohm \: law \\ i = \frac{v}{r} \\ i = \frac{12}{4.8} = 2.5$

In a parallel circuit, the potential difference across each component is same. Thus, potential difference across the conductor = 12 V

Answer 2

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