Chemistry, asked by AmishaKhetwal65471, 11 months ago

Electrode potential for Mg electrode varies according to the
equation
EMg²⁺ /Mg = Eϴ Mg²⁺/Mg - 0.059/2 log 1/[Mg²⁺]. The graph
of E Mg²⁺ /Mg vs log [Mg²⁺] is

Answers

Answered by Anonymous
2

Explanation:

equation

EMg²⁺ /Mg = Eϴ Mg²⁺/Mg - 0.059/2 log 1/[Mg²⁺]. The graph

of E Mg²⁺ /Mg vs log [Mg²⁺] is amswer

Answered by Fatimakincsem
2

Thus the value of m in the slope of the graph is m = 0.05 g / 2

Explanation:

E = Eo - 0.05 g /2 log 1 /[Mg2+]

Graph E Vs log [Mg2+]

E = Eo + 0.05 g /2 log [Mg2+]

E along y axis

Y = mx + c

c = Eo Mg2+ | Mg

m = 0.05 g / 2

Thus the value of m in the slope of the graph is m = 0.05 g / 2

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