Question

Electrode potential of hydrogen electrode is 18 mv then h+ is

Answer 1

Answer:

we have equation for standard reduction potential as

2H+ +2e- ------H2

we have

E=E0 -.059/nlog[H]/[H+]^2

E0=0

n=2

[H]=1

E=-.06/2*log[H+]^-2

E=-log[H+]*(-.06)

=pH*.06=10*.6=-.6V

Thus the potential of hydrogen electrode whose ph is 10 is -.6V

Answer 2

Given:

Electrode potential of hydrogen electrode = 18mv

To Find:

The value of H+

Solution:

A potential of the electrode often acts as the cathode and the standard hydrogen electrode acts as the anode.

Hydrogen electrode can be written as =

18 × 10 −3  = 0 + 0.0591/1log [H+]

log {H+] = 0.3

[H+] = antilog ( 0.3M)

Thus,

= 1.995M ~~ 2

Answer: The value of H+ is 2M.