Question

Electrolysis of dilute aqueous nacl solution was carried out by passing 10ma current the time required to liberate 0.01mole at cathode is? (1F=96500C).
SOLVE THE QUESTION BY FARDAYS LAW OF ELECTROLYSIS EQUATION..​

Answer 1

0.01 moles of H2 will 4 require 2× 0.01=

0.02 moles of electron or 0.02 Faraday.

$\bold \color{red}\frac{I(A) × t(s)}{96500} = 0.02$

$\bold \color{pink} \frac{10mA}{100mA/A} \times t(s) \96500 = 0.02$

$\bold \color{purple}t = 19.3 \times 10⁴s$

Answer 2

0.01 moles of H2 will 4 require 2× 0.01=

0.02 moles of electron or 0.02 Faraday.

\bold \color{red}\frac{I(A) × t(s)}{96500} = 0.02

96500

I(A)×t(s)

=0.02

\bold \color{pink} \frac{10mA}{100mA/A} \times t(s) \96500 = 0.02

100mA/A

10mA

×t(s)\96500=0.02

\bold \color{purple}t = 19.3 \times 10⁴st=19.3×10⁴s