Question

Electrolysis of water is a decomposition reaction. The mole ratio of oxygen and hydrogen gases
liberated during electrolysis of water is​

Answer 1

Answer

1 : 2

$\rule{200}2$

Explanation

Electrolysis of water decomposes water ($\sf H_2O$) into $\sf H_2$ and $\sf O_2$

The balanced reaction is written as -

$\sf 2H_2O(l) \Rightarrow 2H_2(g) + O_2(g)$

We can see that 2 moles of water is decomposing into 2 moles of hydrogen gas and 1 mole of oxygen gas.

Hence, ratio of moles of oxygen to hydrogen liberated is 1 : 2.

$\rule{200}2$

More information :

★ Oxygen gas is liberated at cathode

★ Hydrogen gas is liberated at Anode

Electrolysis

★ The process by the which water is decomposed into hydrogen and oxygen gas by the use of electricity is electrolysis. Electrolysis is an example of electro decomposition reaction.

★ Electrolysis requires two electrodes, an anode and a cathode. Anode is positive charged and carries out oxidation. Cathode is negative charged and reduction occurs here.

★ An electrolyte is also required to carry out electrolysis. Electrolyte is a compound used to help in faster ionisation of compounds undergoing electrolysis. Hydrochloric acid is one such electrolyte.

Answer 2

Answer:

Explanation:

The two moles of water is decomposing into 2 moles of hydrogen gas or 1 moles of oxygen gas .

Thus 1:2 of oxygen and hydrogen gases liberated during electrolysis of water .