Question

Electrolytic conductivity of 0.30 m solution of kcl at 298 k is 3.72 × 10–2 s cm–1. Calculate its molar conductance

Answer 1

Answer:Given that ,

? = 0.0248 S cm?1 �and c = 0.20 M

Formula of molar conductivity,

?m = ( k � 1000)/M

?m =(0.0248 � 1000 )/0.2  

?m =124 S cm2 mol?1

Answer 2

Molar conductance is 124 $Scm^2mol^{-1}$

Explanation:

Molar conductance is defined as the conductance of all the ions produced by ionization of 1 g mole of an electrolyte when present in V mL of solution.

$\mu=\frac{\kappa\times 1000}{C}$

where,

$\mu$ = molar conductance = ?

$\kappa$ =Specific conductance = $3.72\times 10^{-2}Scm^{-1}$

C= concentration of the solution in mole per litre = 0.30 M

$\mu=\frac{3.72\times 10^{-2}Scm^{-1}\times 1000}{0.30M}=124Scm^2mol^{-1}$

Molar conductance is 124 $Scm^2mol^{-1}$

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