Chemistry, asked by Afsha9558, 11 months ago

Electromagnetic radiation of wavelength 242nm is just sufficient to ionise na atom.The ionisation energy of na in kj mol-1

Answers

Answered by 007theabhishek
2

Answer:

8.21*10^{-19}kJ

Explanation:

the given wavelength of an electromagnetic radiation is= 242nm= 242*10^{-9}m

the energy associated with this wavelength can be calculated by the formula

E=hc//\

here E stands for energy

h stands for Plank's constant whose value is 6.626*10^{-34} Js

c is the speed of light whic is equal to 3*10^{8}m/s

/\ stands for the  wavelength

so

E=6.626*10^{-34} * 3*10^{8} / 242*10^{-9} = </p><p>8.21 * 10^{-19}kJ

since it is the minimum energy required to remove valence election from Na...it is the I.E. of Na

So I.E. energy of Na is 8.21 * 10^{-19}kJ

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