electromotive force and internal resistance of a cell is 10V and 2 ohm respectively. the cell is now connected with a 4 ohm resistor. how much heat (in joule) will be generated in the resistor in 60 second?
Answers
Answer:
The total resistance of a circuit
connected to the given cell of emf 15
V is the sum of all the resistances from
various sources like, resistors, ammeter,
voltmeter, etc., connected in series along
with the internal resistance of the cell.
In this case, the total resistance is given
as 30+30+60=120hms.
From the ohm's law the total current can
be calculated from the formula I=V/R.
That is, I=
R
V
12A
15V
=1.25A.
Hence, the current through the battery is
1.25 amperes.
The voltage output of a device is
measured across its terminals and is
called its terminal voltage V. Terminal
voltage is given by the equation V=emf-Ir
where, r is the internal resistance and I
is the current flowing at the time of the
measurement.
Therefore, V=15V-(1.25×3)=11.25V.
Hence, the potential difference across
the terminals of the cell is 11.25V
Hope it's help you..
Answer:
Net emf of the combination of cell E=200−10=190 V
Net resistance of the circuit R=38Ω
So, current in the circuit I=
R
E
⟹ I=
38
190
=5 A