Question

Electron configuration for mn7+

Answer 1

Answer:

[Ar]18 3d5

Explanation:

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Answer 2

Answer:

The electron configuration of $Mn^{7+}$ is $1s^{2} 2s^{2}2p^{6} 3s^{2} 3p^{6}$

Explanation:

The electronic configuration is the arrangement of the electrons of an atom or molecule in atomic or molecular orbitals.

That is the electronic configuration is the distribution of electrons in an atom.

The atomic number of manganese = 25

The electronic configuration of manganese(Mn) = $1s^{2} 2s^{2}2p^{6} 3s^{2} 3p^{6}4s^{2} 3d^{5}$

The total number of electrons present in $Mn^{7+}$ ion = 25 - 7 = 18

Therefore the electronic configuration of $Mn^{7+}$ ion = $1s^{2} 2s^{2}2p^{6} 3s^{2} 3p^{6}$