Question

Electron dot structure of methane and propanol

Answer 1

see figure, here you can get dot structure of methane (CH4) and propanol (C3H6O).

how to draw dot structure :

step 1 : find the number of Valence electrons.

for carbon , C ⇒4 ( so, four more electrons require to be stable configuration like Ne)

for hydrogen , H ⇒1 (so, one more electrons require to be stable configuration like He )

for Oxygen , O ⇒6 (so, two more electrons require to be stable configuration like Ne )

step 2 : determine the number of bonds in the molecule.

as we know, each covalent bond formed requires two electrons, so number of bonds in the molecule is half the number of electrons needed.

for methane (CH4) , (four electrons needed for C and one electron needed for each H atom )

so, number of bond = (4 + 1 × 4)/2 = 4

similarly, number of bond in propanol = (3 × 4 + 6 × 1 + 2 × 1)/2 = 10

step 3 : choose central atom

generally, lowest electronegative atom will be central atom or, the atom which has highest Valence electrons will be central atom.

for methane, C is central atom.

for propanol, all thre C atoms are central atoms.

step 4 : now let's draw dot structure of methane and propanol.

for each bond, draw two dots as shown in figure.

finally you will get dot structure of methane and propanol.

Answer 2

Explanation:

the vapour pressure of an aqueous solution of 1 mole glucose at 16 degree Celsius