Question

Electron, proton and He++ are moving with same

KE. Then order of de-Broglie wavelength are ​

Answer 1

Physics

If an electron and a proton have the same de-Broglie wavelength, then the kinetic energy of the electron is :

Medium

Answer

de Broglie wavelength λ=

2mK

h

We get K=

2mλ

2

h

2

⟹ K∝

m

1

We know that m

p

>m

e

∴

K

p

K

e

=

m

e

m

p

>1

⟹ K

e

>K

p