Question

Electronegativity value of hydrogen is 2.1 and that of sodium is 1. Find out the nature of
bonding present in the compound, when hydrogen combines with fluorine and hydrogen
combines with sodium. (Electronegativity value of fluorine is 4).​

Answer 1

Answer:

HF is a covalent bond and Nah is a ionic bond

Answer 2

Sodium hydride is covalent whereas hydrogen fluoride is ionic.

Explanation:

• The electronegativity of the elements is defined as the tendency of an element to attract the bonded pair of electrons towards itself.

• The electronegativity of fluorine is 4, that of hydrogen is 2.1 and that of sodium is 1.

• In sodium hydride, the electronegativity difference of the elements is 2.1 - 1 = 1.1.

• In hydrogen fluoride, the electronegativity difference is 4 - 2.1 = 1.9.

• So as the difference is more in HF than in NaH, so HF is more ionic than NaH.

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